 Tip #497: Replacing a string with default buffer contents
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| created: |
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June 27, 2003 12:27 |
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complexity: |
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basic |
| author: |
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Adam Wolff |
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as of Vim: |
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6.0 |
It's common to replace a given string in a file with something that appears elsewhere in the file. Often I don't think to put the replacement string in a named register, so it's hard to delete the text I'm replacing without replacing what's in the default (@") copy register -- :let is too cumbersome for this. (BTW, is there a way to issue a command like 'd' or 'c' *without* replacing what's in @"?)
Anyway, I've been using this map
vmap R :<BACKSPACE><BACKSPACE><BACKSPACE><BACKSPACE><BACKSPACE>:let @9=@"<CR>gvx"9P
which replaces what's highlighted in visual mode the contents of ""
It's ugly though (all the backspaces are necessary to delete the default :'<,'> that shows up when you start a command in visual mode.)
I find this useful enough that I use it, but what I really want is something similar where I could type say
R3w
(where R is remapped to my special command) that replaces the next three words the contents of @"
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Additional Notes
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niklasl,
June 28, 2003 3:44
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Afaik, Vim already works like your mapping. If you press 'p' when in visual mode, the selected text is replaced by the contents of the default register ('"<chosen_register>p' works as well). The deleted text is yanked as if deleted normally.
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Anonymous,
June 28, 2003 9:42
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"_d deletes to the black hole register and does not change any normal register
See :help "_
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Maurice,
June 28, 2003 18:26
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And you can replace these <backspace>'es with one <c-u>
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Anonymous,
June 30, 2003 11:54
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| black hole buffer. just what I was looking for. gracias
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